0=49q^2-81

Solution for 0=49q^2-81 equation:

0=49q^2-81

We move all terms to the left:

0-(49q^2-81)=0

We add all the numbers together, and all the variables

-(49q^2-81)=0

We get rid of parentheses

-49q^2+81=0

a = -49; b = 0; c = +81;
Δ = b2-4ac
Δ = 02-4·(-49)·81
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126}{2*-49}=\frac{-126}{-98}
=1+2/7
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126}{2*-49}=\frac{126}{-98}
=-1+2/7
$